What would the Hall voltage be if a 2.00-T field is applied across a 10-gauge copper wire (2.588 mm in diameter) carrying a 20.0-A current

The hall  voltage is

Explanation:

From the question we are told that

     The magnetic field is  

     The diameter is  

       The  current is  

The radius can be evaluated as

substituting values

The hall voltage is mathematically represented as

where is the  drift velocity of the electrons on the current carrying conductor which  is mathematically evaluated as

Where n is the number of electron per cubic meter which for copper is  

  A is the cross - area of the wire  which is mathematically represented as

substituting values

so the drift velocity is  

Thus the hall voltage is

the force on the thing and the distance the force moves the thing

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.