A soap bubble of radius R is situated in a uniform electric field of magnitude E. The electric flux through the surface of the soap bubble is

The electric flux around the soap bubble will be

Ф = q/ε

Explanation:

The radius of the soap bubble = R

The electric field around the soap bubble = E

The electric flux = ?

The soap can be approximated to be a sphere, so we find the surface area of the sphere

For the soap bubble, the surface area will be

A =  

Recall that electric flux is given as

Ф = EA

substituting value of A from above, we'll have

Ф = E..... equ 1

Also recall that the electric field E is given as

E = q/(4πε)

substitute the value of E into equ 1, to get

Ф = q/(4πε) *

The electric flux around the soap bubble reduces to

Ф = q/ε

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.

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