long nonconducting cylinder (radius = 12 cm) has a charge of uniform density (5.0 nC/m3) distributed throughout its volume. Determine the magnitude of the electric field 15 cm from the axis of the cylinder.

the magnitude of the electric field  = 27.1058 V/m

≈ 27 V/m

Explanation:

given

R(radius enclosed) = 12 cm = 0.12 m

ρ(charge density) = 5.0 nC/m³ = 5.0 × 10⁻⁹C/m³

r(radius from the axis) = 15 cm = 0.15 m

using Gauss law, which states that the electric flux through any closed surface is directly proportional to the total electric charge enclosed by this surface.

attached is the calculation of the question, using Gauss law of electrostatics

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

thermal energy is the answer