a playground merry-go-round of radius r = 2.20 m has a moment of inertia i = 245 kg · m2 and is rotating at 11.0 rev/min about a frictionless vertical axle. facing the axle, a 26.0-kg child hops onto the merry-go-round and manages to sit down on the edge. what is the new angular speed of the merry-go-round?

8.92 rpm

Explanation:

Given that

Radius of the merry go round, r = 2.2 m

Initial moment of inertia, I1 = 245 kgm²

Initial speed of rotation, w1 = 11 rpm

Mass of the child, m = 26 kg

To solve the problem, we use the law conservation of momentum

I1w1 = I2w2

I2 = mr² + I1

I2 = 245 + 26 * 2.2

I2 = 245 + 57.2

I2 = 302.2 kgm²

Now, applying the formula, we have

I1w1 = I2w2

245 * 11 = 302.2 * w2

w2 = 2695 / 302.2

w2 = 8.92 rpm

Thus, the new angular speed of the merry go round is 8.92 rpm

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answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.