The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that we can still apply Gauss's law to a Gaussian surface that is entirely within an insulator by replacing the right-hand side of Gauss's law, Qin/eo, with Qin/e, where ε is the permittivity of the material. (Technically, Eo is called the vacuum permittivity.) Suppose that a 70 nC point charge is surrounded by a thin, 32-cm-diameter spherical rubber shell and that the electric field strength inside the rubber shell is 2500 N/C. What is the permittivity of rubber?

The permittivity of rubber is  

Explanation:

From the question we are told that

     The  magnitude of the point charge is  

      The diameter of the rubber shell is  

       The Electric field inside the rubber shell is  

The radius of the rubber is  mathematically evaluated as

Generally the electric field for a point  is in an insulator(rubber) is mathematically represented as

Where is the permittivity of rubber

    =>    

   =>      

substituting values

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