A thin layer of turpentine (n=1.472n=1.472) is floating on water (n=1.333n=1.333). Light of wavelength 589 nm travels from air into the turpentine. At what angle should the light be incident on the turpentine-water interface so that all the light totally internally reflects in the turpentine and does not travel into the water?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.