Physics, 22.07.2020 18:01 shady1095

A certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a current density of What is the diameter of the wire in the fuse?

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Answer from: fvwk

The value of the diameter of the wire is 0.45 mm.

Given that:

Current in the fuse = 1 Ampere

Current density = 620 A/cm²

Area of the wire = $\dfrac{\text I}{\rho}$

Area = $\dfrac{1}{620}$

Area = 1.613 x 10⁻³ cm²

Also, we know that:

10000 cm² = 1 m²

1.613 x 10⁻³ cm² = 1.613 x 10⁻⁷ m²

The area of a wire can be calculated as:

Area = $\dfrac{\pi \text d^2}{4}$

where, d = diameter

Substituting the values in the above equation, we get:

1.613 x 10⁻⁷ = $\dfrac{3.14 \times \text d^2}{4}$

6.448 x 10⁻⁷ = 3.142 x d²

Hence, the value of d will be:

d² = 2.05 x 10⁻⁴

d = $\sqrt{2.05 \times 10^{-7}}$

d = 4.5 x 10⁻⁷

Thus, the value of the diameter of the wire is 0.45 mm.

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Answer from: potaetoo1997

0.45 mm

Explanation:

The complete question is

a certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a current density of 620 A/ cm^2. What is the diameter of the wire in the fuse?

A) 0.45 mm

B) 0.63 mm

C.) 0.68 mm

D) 0.91 mm

Current in the fuse is 1.0 A

Current density of the fuse when it melts is 620 A/cm^2

Area of the wire in the fuse = I/ρ

Where I is the current through the fuse

ρ is the current density of the fuse

Area = 1/620 = 1.613 x 10^-3 cm^2

We know that 10000 cm^2 = 1 m^2, therefore,

1.613 x 10^-3 cm^2 = 1.613 x 10^-7 m^2

Recall that this area of this wire is gotten as

A = $\frac{\pi d^{2} }{4}$

where d is the diameter of the wire

1.613 x 10^-7 = $\frac{3.142* d^{2} }{4}$

6.448 x 10^-7 = 3.142 x $d^{2}$

$d^{2}$ = $\sqrt{ 2.05*10^-7}$

d = 4.5 x 10^-4 m = 0.45 mm

Answer from: Quest

Answer: it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.explanation: we have equation of motion $s=ut+\frac{1}{2} at^2$ ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/s $s=0*t+\frac{1}{2} *2.18*t^2$ $s=1.09t^2[/ 2equating equation 1 and 2 [tex]4.75t = 1.09t^2\\ \\ t=4.36 seconds.$ so it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.

Answer from: Quest

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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A certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a cu...

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