A simple pendulum of length 1.62 m has a mass of 117 g attached. It is drawn back 38.0 degrees and then released. What is the maximum speed of the mass

The maximum speed of the mass is 4.437 m/s.

Explanation:

Given;

length of pendulum, L = 1.62 m

attached mass, m = 117 g

angle of inclination, θ = 38°

This mass was raised to a height of

h = 1.62 - cos38° = 1.0043 m

Apply the principle of conservation of mechanical energy

PE = KE

mgh = ¹/₂mv²

v  = √(2gh)

v = √(2 * 9.8 * 1.0043)

v = 4.437 m/s.

Therefore, the maximum speed of the mass is 4.437 m/s.

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

not too sure thinking all accelerations are pointed down