.- Un cuerpo es lanzado con una velocidad de 20 m/s, formando un ángulo con la horizontal de 50o, determinar el tiempo de vuelo, el alcance máximo y la altura máxima

- t = 3.12s

- x = 40.19m

- h_max = 11.97m

Explanation:

- In order to calculate the flight time of the body, you use the following formula:

        (1)

vo: initial speed  = 20m/s

g: gravitational acceleration = 9.8 m/s^2

θ: angle with the horizontal of the direction of the motion of the body = 50°

You replace the values of the parameters in the equation (1):

The flight time of the body is 3.12s

- The maximum range of the motion is given by:

where you have used the flight time.

The maximum horizontal distance traveled by the body us 40.19m

- The maximum height is:

             (2)

you replace the values of the parameters:

The maximum height is 11.97 m

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west