A lunar module weighs 12 metric tons on the surface of the Earth. How much work is done in propelling the module from the surface of the moon to a height of 80 miles

149.05J

Explanation:

Hello,

Data;

Weight = 12N

x = 80miles

Radius of the moon = 1079.4mi

W = mg

But gravity at moon = ⅙ the gravity on earth

12 = ⅙ × m

M = 2kg

Mass of the module = 2kg

K = F.x

F(x) = k / x²

2 = k / (1079.4)²

k = 2.33×10⁶

Work = ∫f.dx

work = ∫₁₀₇₉.₄¹¹⁵⁹ . (2.33×10⁶/x²).dx

Work = (-2.33×10⁶) ×(¹/₁₁₅₉ - ¹/₁₀₇₉)

work = 149.05J

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

the independent variable, or the one that is intentionally manipulated is the speed.