A 0.110 m radius, 506-turn coil is rotated one-fourth of a revolution in 4.17 ms, originally having its plane perpendicular to a uniform magnetic field. (This is 60 rev/s.) Find the magnetic field strength needed to induce an average emf of 10,000 V. 519.893 Incorrect: Your answer is incorrect.

Explanation:

Expression for emf induced = 1 /2 B n r²ω where B is magnetic field , r is radius of the coil and ω is angular velocity of rotation , n is no of turn .

ω = 2πf = 2π x 60 = 120 π   ; where f is frequency of rotation .

emf induced =  1 /2 B r²x 120π x n

Putting the given values

10000 = .5 x B x .11² x 120 x 3.14 x 506

B = 8.67 T .

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge