A physicist is designing a cyclotron to accelerate protons to one-tenth the speed of light. The magnetic field will have a strength of 1.6 T. (a) Determine the rotational period (in s) of the circulating protons. s (b) Determine the maximum radius (in m) of the protons' orbit

(a)     T = 4.09*10^-8 s

(b)     r = 0.19m

Explanation:

(a) In order to determine the rotational period of the protons, you first calculate the angular speed of the proton. You use the following formula for the radius of the trajectory described by the electron in a region with a constant magnetic field:

              (1)

m: mass of the proton = 1.67*10^-27 kg

q: charge of the proton = 1.6*10⁻19C

B: magnitude of the magnetic field = 1.6T

v: speed of the proton = 0.1c = 0.1(3*10^8m/s) = 3*10^7m/s

The angular speed of the proton is v/r, then, you solve for w in the equation (1) and replace the values of the parameters:

The rotational period T is:

(b) The radius of the protons' orbit is calculated by using the equation (1):

The radius of the protons' orbit is 0.19m

ill do it for 100, also this isnt 80 its 40

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right