The electric field everywhere on the surface of a thin, spherical shell of radius 0.770 m is of magnitude 892 N/C and points radially toward the center of the sphere. (a) What is the net charge within the sphere's surface

Q = 58.8 nC

Explanation:

For distance just above the surface of the spherical shell and higher, electric field of the shell can be considered as the electric field generated by a charge Q at the center of the spherical shell:

To calculate the net charge within the sphere's surface you use the following formula:

        (1)

Q: net charge of the spherical shell

R: radius of the sphere = 0.770m

E: magnitude of the electric field for points just above the sphere's surface = 892N/C

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

You solve the equation (1) for Q and replace the values of the other parameters:

The net charge within the sphere's surface is 58.8nC

explanation:

earth's surface is mainly heated by the absorption of infrared radiation from the sun.

evaporation occurs because molecules in liquid water are warmed ( usually by the sun) and vibrate quicker, becoming less dense and rise.

condensation occurs because molecules in water vapor are cooled and therefore vibrate more slowly thus becoming more dense and eventually fall to earth.

lines of equal barometric pressure on a weather map are called: isobars : lines of equal temp on a weather map are called: isotherms.​

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2