Physics, 15.07.2020 08:01 jenah6114

Water flows over a section of Niagara Falls at the rate of 1.2×106 kg/s and falls 50.0 m. How much power is generated by the falling water?

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Answer from: kimberlyalonso6697

This question involves the simple concept and formula of Power.

The power generated by the falling water is "5.88 x 10⁸ W".

Power can be defined as the energy applied per unit of time.

$Power = \frac{Energy}{Time}$

here, the energy is the potential energy, due to the fall of water:

$Power = P = \frac{mgh}{t}$

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 50 m

$\frac{m}{t}$ = mass flow rate = 1.2 x 10⁶ kg/s

Therefore,

$P = (1.2\ x\ 10^6\ kg/s)(9.81\ m/s^2)(50\ m)\\$

P = 5.88 x 10⁸ W

Learn more about power here:

link

The attached picture explains the concept of work, power and energy.

Answer from: jlayne0605

5.88×10⁸ W

Explanation:

Power = energy / time

P = mgh / t

P = (m/t) gh

P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)

P = 5.88×10⁸ W

Water flows over a section of Niagara Falls at the rate of 1.2×106 kg/s and falls 50.0 m. How much p

Answer from: Quest

Ithink the answers is a i hope it my friend message me if i’m wrong and i’ll change my answer and fix it for you

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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Water flows over a section of Niagara Falls at the rate of 1.2×106 kg/s and falls 50.0 m. How much p...

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