You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a voltage source that has a voltage amplitude of 30.0 V and an angular frequency of 220 rad/s . Part A: What is the impedance of the circuit? ( Z = ? Ω )
Part B: What is the current amplitude? ( I = ? A )
Part C: What is the voltage amplitude across the resistor? ( VR = ? V )
Part D: What is the voltage amplitudes across the inductor? ( VL = ? V )
Part E: What is the phase angle ϕ of the source voltage with respect to the current? ( ϕ = ? degrees )
Part F: Does the source voltage lag or lead the current? ( the voltage lags the current OR the voltage leads the current )

A.  Z = 185.87Ω

B.  I  =  0.16A

C.  V = 1mV

D.  VL = 68.8V

E.  Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

      (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

                    (2)

V: voltage amplitude = 30.0V

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

           (3)

D. The voltage across the inductor is:

E. The phase difference is given by:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.