A 1.30-kg particle moves in the xy plane with a velocity of v with arrow = (4.50 î − 3.30 ĵ) m/s. Determine the angular momentum of the particle about the origin when its position vector is r with arrow = (1.50 î + 2.20 ĵ) m.

The angular momentum of the particle about the origin is .

Explanation:

Vectorially speaking, the angular momentum is given by the following cross product:

This cross product can be solved with the help of determinants and its properties, that is:

The 3 x 3 determinant is solved by the Sarrus Law:

If , and , the angular momentum of the particle about the origin is:

The angular momentum of the particle about the origin is .

answer; how far out of place which the object finished relative to the starting location;