A particle of mass m = 9 kg s moving along a guide wire with shape given by y(x) = - cos(2.5x) m, where x is in meters. Gravity g = -9.8j m/s^2 acts vertically. At the current instant the particle has x = 11 m and it is moving to the right with a speed of y = 1 m/s, which is increasing at a rate of 2 m/s^2. What is the force F of the wire on the particle?

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

the answer is 3.1 his answer is wrong mines is right

im guessing the west of station b