In the game of billiards, all the balls have approximately the same mass, about 0.17 kg. In the figure, the cue ball strikes another ball such that it follows the path shown. The other ball has a speed of 1.5 m/s immediately after the collision. What is the speed (in m/s) of the cue ball after the collision?

v = 2.6 m/s  

Explanation:

The question is incomplete because the diagram is not given in the question.

The diagram of this question is attached below.

According to the law of conversation of momentum.

mv(initial) = mv(final)

We can see in the diagram that:

mv(initial) = 3 × 0.17

mv(final) = mv₁(final) + mv₂(final)

Consider only the horizontal components of velocities, to compare them to initial velocity.

mv(final) = mv₁(final) + mv₂(final)

0.17 × 3  = (0.17)(v)(cos 30) + (0.17)(1.5)(cos 60)

0.51 = 0.1472v + 0.1275

0.3825 = 0.1472v

v = 2.6 m/s  

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