A ball is thrown straight up in the air at an initial speed of 30 m/s. At the same time the ball is thrown, a person standing 70 m away begins to run toward the spot where the ball will land. How fast will the person have to run to catch the ball just before it hits the gro

11.44 m/s

Explanation:

We are given;

Initial Speed of ball;v_o = 30 m/s

Distance from person to ball;d = 70 m

Now, from projectile motion, the ball will hit the ground in time given by the formula;

t = (2v_o)/g

Wherr;

t is time taken

v_o is initial velocity

g is acceleration due to gravity

Plugging in the values with g = 9.8 m/s² as acceleration due to gravity, we have;

t = 2(30)/9.8

t = 6.12s

Now, the person will need to run 70m in 6.12s

We know that velocity/speed = distance/time

Thus;

Speed = 70/6.12

Speed = 11.44m/s

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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