A square conducting plate 52.0 cm on a side and with no net charge is placed in a region, where there is a uniform electric field of 82.0 kN/C directed to the right and perpendicular to the plate. Find
(a) the charge density of each face of the plate and
(b) the total charge on each face.

Explanation:

Given:  uniform electric field E= 82.0 kN/C.

a) charge density σ =ε_0 E.

therefore,

b)Total charge on each face = σA

q=σA

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  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂