A positively charged particle initially at rest on the ground accelerated upward to 100m/s in 2.00s. If the particle has a charge-to-mass ratio of 0.100 C/kg and the electric field in this region is constant and uniform, what are the magnitude and direction of the electric field?

Explanation:

From the question we are told that

     The initial velocity is  

       The time taken is  

       The charge to mass ratio is  

Generally the acceleration is mathematically evaluated as

substituting values  

The electric field is mathematical represented as

substituting values

the correct answer is b

potential energy is directly proportional to height.

more height = more potential energy.

greatest increase in height = greatest increase in potential energy

where are the points with the greatest increase in height ?

has to be c-e or d-e .