At what rate must a cylindrical spaceship rotate if occupants are to experience simulated gravity of 0.50 gg? Assume the spaceship's diameter is 35 mm , and give your answer as the time needed for one revolut

Time needed for one revolution is 0.38 s

Explanation:

The formula for the frequency of rotation of a spaceship, to create the desired artificial gravity, is as follows:

f = (1/2π)√(a/r)

where,

f = frequency of rotation = ?

a = artificial gravity required = 0.5 g

g = acceleration due to gravity on surface of Earth = 9.8 m/s²

r = radius of ship = 35 mm/2 = 17.5 mm = 17.5 x 10⁻³ m

Therefore,

f = (1/2π)√[(0.5)(9.8 m/s₂)/(17.5 x 10⁻³ m)]

f = 2.66 Hz

Now, for the time required for one revolution, is given as:

Time Period = T = 1/f

T = 1/2.66 Hz

T = 0.38 s

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg