Magnet A has thrice the magnetic field strength of magnet B and at a certain distance pulls on magnet B with a force of 100 Newtons. With how much force, then, does magnet B pull on magnet A? What is the force if the distance between the magnets is doubled?

- The force that magnet B pulls on the magnet A is equal to the force that magnet A pull on B. That is , 100N.

-   F'B = 25N

Explanation:

- You have that the magnet A pulls on the magnet B with a force of 100N.

By the third Newton law you have that any force has a reaction, that is, the force that magnet B pulls on the magnet A is equal to the force that magnet A pull on B. That is , 100N.

-  In order to calculate the force, if the distance between magnets is twice, you first take into account that the magnetic force is inversely proportional to the force between magnets, as follow:

    (1)

FB: magnetic force between the magnets = 100N

If the distance is twice, you obtain:

The new force is a quarter of the initial force, that is:

If the distance is twice the force is a quarter of the initial force.

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  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz