A 56.0 g ball of copper has a net charge of 2.10 μC. What fraction of the copper’s electrons has been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)

The fraction of the cooper's electrons that is removed is .

Explanation:

An electron has a mass of and a charge of . Based on the Principle of Charge Conservation, in electrons must be removed in order to create a positive net charge. The amount of removed electrons is found after dividing remove charge by the charge of a electron:

The number of atoms in 56 gram cooper ball is determined by the Avogadro's Law:

Where:

- Mass of the ball, measured in kilograms.

- Atomic mass of cooper, measured in grams per mole.

- Avogradro's Number, measured in atoms per mole.

If , and , the number of atoms is:

As there are 29 protons per each atom of cooper, there are 29 electrons per atom. Hence, the number of electrons in cooper is:

The fraction of the cooper's electrons that is removed is the ratio of removed electrons to total amount of electrons when net charge is zero:

The fraction of the cooper's electrons that is removed is .

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