Alan leaves Los Angeles at 8:00 a. m. to drive to San Francisco, 400 mi away. He travels at a steady 45.0 mph . Beth leaves Los Angeles at 9:00 a. m. and drives a steady 55.0 mph . a. Who gets to San Francisco first?
b. How long does the first to arrive have to wait for the second?

a.Beth

b.2232 s

Explanation:

We are given that

Distance,d=400 mi

Speed of Alan,v=45 mph

Speed of Beth,v'=55 mph

a.Time =

Using the formula

Time taken by Alan=

Time taken by Beth=

Alan will reach San Francisco at 4:53 PM

Beth will reach San Francisco at 4:16 PM

Beth will reach before Alan.

b.Difference between time=8.89-7.27=1.62 hr

t=1.62 hr

1.62-1=0.62 hr

0.62 hr=

Hence, Beth has to wait 2232 s for Alan to arrive .

vapour or gas assuming atmospheriv pressure

490 n

f=125n a=2.5m/s2