A driver moves with initial velocity of 40m/s accelerates uniformly at a rate of 12m/s2.  It attains a velocity 52m/s. calculate the distance covered during the journey.

The total distance covered is 46m

Explanation:

From the question, we have the following given parameters.

Initial Velocity = 40m/s

Acceleration = 12m/s²

Final Velocity = 52m/s

Required

Calculate the distance covered during the journey

The question can be solved using the following equation of motion.

v² = u² + 2as

Where

v = final velocity = 52m/s

u = initial velocity = 40m/s

a = acceleration = 12m/s²

s = distance = ?

By substituting the above values in the stated formula

v² = u² + 2as becomes

52² = 40² + 2 * 12 * s

2704 = 1600 + 24s

Subtract 1600 from both sides

2704 - 1600 = 1600 - 1600 + 24s

1104 = 24s

Divide both sides by 24

1104/24 = 24s/24

46 = s

Reorder

s = 46

Hence, the total distance covered is 46m

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg