Hence, the force of gravitation between Earth and Jupiter is 8.16 * 10 N Enample 5: An apple with the mass of 200 g falls from a tree. What is the acceleration
of the apple towards the earth? What is the acceleration of the earth towards the apple?
(Given: mass of the earth = 6*10kg radius of the earth 6.4 10 m, G=6.67 * 10 " Nm
kg and neglecting height of the tree).

Acceleration of the apple towards the earth is: 9.7705 m/s2.

Acceleration produced on earth towards the apple

Explanation:

Given :

We have to convert into the kg ,

so

M= kg

As the gravitational force is existing among the earth and the apple

so

Putting the value of G,M,m and , we get

Consider a1 and a2 be a acceleration due to the gravitational force of earth attraction created on the apples

F= a1 *m

a1=

Acceleration of the apple towards the earth is: 9.7705 m/s2.

again

a2=

So, Acceleration produced on earth towards the apple

i think the answer is b

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j