At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 65.9 V/m. Find the magnetic field strength B, the total energy density u, and the power flow per unit area, all at the same instant and location.

B = 2.19*10^-7 T

u = 1.92*10^-18 J/m^3

P = (4pi r^2)cεo E^2

Explanation:

In order to find the magnetic field strength of the electromagnetic wave you use the following formula:

    (1)

B: magnitude of the magnetic field

E: magnitude of the electric field = 65.9V/m

c: speed of light = 3*10^8m/s

The magnitude of the magnetic field 2.19*10^-7 T

The energy density of the electromagnetic wave is:

      (2)

εo: dielectric permittivity = 8.85*10^-12C^2/Nm^2

The energy density of the electromagnetic wave is 1.92*10^-8J/m^3

The power is given by:

convex lenses are thicker at the middle. rays of light that pass through the lens are brought closer together (they converge). a convex lens is a converging lens. when parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus.