Q3. A car is initially heading east at 55.0 km h when it turns a corner and heads N 55° Eat 65.0 km h -1. Determine the change in the velocity of the car during this time.

37.3 km/h at N 2.70° E

Explanation:

Find the horizontal and vertical components of the initial velocity (u) and final velocity (v).  Remember that N 55° E means 55° east of north.

uₓ = 55.0 km/h

uᵧ = 0 km/h

vₓ = 65.0 km/h × sin 55° = 53.24 km/h

vᵧ = 65.0 km/h × cos 55° = 37.28 km/h

Find the difference.

vₓ − uₓ = -1.76 km/h

vᵧ − uᵧ = 37.28 km/h

The magnitude is:

|v − u| = √((-1.76 km/h)² + (37.28 km/h)²)

|v − u| = 37.3 km/h

The direction is:

θ = tan⁻¹(37.28 / -1.76)

θ = 92.70°

θ = N 2.70° E

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.

current flows in a wire