HELP PLZ! A parachutist jumps out of an aeroplane and accelerates uniformly at 9.8 ms-2 for ten seconds. a. How far does she travel? b. What is her final velocity?

a.) 490m

b.) 98m/s

Explanation:

Given that the

Acceleration g = 9.8 m/s^2

Time = 10s

Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,

U = 0

Distance covered = height H

The height can be calculated by using second equation of motion

H = Ut + 1/2gt^2

Substitute g and t into the formula

H = 1/2 × 9.8 × 10^2

H = 490 m

Therefore, she travels as far as 490 m

b.) Her final velocity can be calculated by using third equation of motion

V^2 = U^2 + 2gH

Substitute g and H into the formula.

Remember that U = 0

V^2 = 2 × 9.8 × 490

V^2 = 9604

V = sqrt (9604)

V = 98 m/s

Therefore, her final velocity is 98 m/s

which statement about this sum is true? −245+2.7

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

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