Three resistors connected in a parallel have individual values of 4.0 ohms, 6.0 ohms, and 10 ohms. If this combination is connected to a 12 V battery, what is the current in the 10 ohm resistor

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electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j