An object that is 0.5 m above the ground has the same amount of potential energy as a spring that is stretched 0.5 m. Each distance is then doubled. How will the potential energies of the object and the spring compare after the distances are doubled?

The gravitational potential energy of the object will be two times greater than the elastic potential energy of the spring.
The elastic potential energy of the spring will be four times greater than the gravitational potential energy of the object.
The elastic potential energy of the spring will be two times greater than the gravitational potential energy of the object.
The potential energies will remain equal to o

C. The elastic potential energy of the spring will be two times greater than the gravitational potential energy of the object.

Explanation:

The formula for the potential energy of an object above the ground is mgh, where h is height. Meanwhile, the potential energy of a stretched spring is 1/2kx^2, where x is the distance stretched. This means that when the distance doubles, the potential energy of the object raised above the ground will be raised by a factor of 2, and the spring by a factor of 2^2=4. Therefore, the correct answer is C. Hope this helps!

c, 1a hope this

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2