An ideal transformer has LaTeX: N_1 = 1000 N 1 = 1000 (number of windings on the primary side), and LaTeX: N_2 = 8000 N 2 = 8000 (number of windings on the secondary side). If the rms voltage on the primary side is LaTeX: V_{rms}=100V V r m s = 100 V , what is the rms voltage on the secondary side? Give your answer in terms of Volts (rms), without entering the units.

V₂ = 800 Volts (rms)

Explanation:

The turns ratio of an ideal transformer is given by the following formula:

N₁/N₂ = V₁/V₂

where,

N₁ = No. of turns in primary coil of the transformer = 1000 N

N₂ = No. of turns in secondary coil of the transformer = 8000 N

V₁ = rms Voltage on primary side of the transformer = 100 V

V₂ = rms Voltage on secondary side of the transformer = ?

Therefore, using these values in equation, we get:

1000 N/8000 N = 100 V/V₂

V₂ = (100)(8) Volts

V₂ = 800 Volts (rms)

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

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