A force of 2500 N is exerted on a piston that has an area of 0.060 m2. What force is exerted on a second piston that has an area of 0.18 m?

F F2
Α1, Α2,

Explanation:

SI LA PRESIÓN ES LA MISMA ENTONCES:

P = 2500 N/ = 41667 Pa

F2 = 41667 Pa() = 7500 N

i will answer your question if you answer mine

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s