an 85 kg construction worker has 37,485 j of gravitational potential energy to the nearest whole number the worker is blank m above the ground. answer the blank = )

The height of construction worker above the ground is of 45 m.

Given data:

The mass of construction worker is, m = 85 kg.

The gravitational potential energy stored in worker is, U = 37,485 J.

We know that the energy of any object by virtue of its position is known as gravitational potential energy. So, the expression for the gravitational potential energy of construction worker is,

U = mgh

here,

g is the gravitational acceleration and h is the height above the ground.

Solving as,

37485 = 85 × 9.8 × h

h = 45 m

Thus, we can conclude that the height of construction worker above the ground is of 45 m.

Learn more about the gravitational potential energy here:

link

45 m above the ground

Explanation:

The formula for height is height = PEg/ mg (gravitational potential energy/ mass times g).

37,485/ (85 kg*9.8m/s^2)

37,485/ 833 = 45 m above the ground

ill do it for 100, also this isnt 80 its 40

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂