Vector a has components ax=1.30cm, ay= 2.25cm; vector b has components bx=4.10cm, by=-3.75cm.

find a. the components of the vector sum a+b;
b. the magnitude and direction of vector a+b;
c. the components of the vector difference b-a;
d. the magnitude and direction of vector b - a.

We  are given with the x and y components of Vector A and B. In this case, we compute the resultant of both components of each vector. The vector is equal to the square root of the sum of the squares of the components. A is equal to 2.60 cm. B is equal to 5.56 cm. B is found in quadrant Iv and has an angle of 42.447 degrees as a terminal angle. A has an angle of 59.98 degrees. 
a. 5.6082 < -15.53 degreesc. 6.63 <-64.98 degreesb. x = 6.63 cos -64.98 degrees = 2.80   y = 6.63 sin -64.98 degrees = -6.00