In an experiment designed to determine the velocity of a bullet fired by a certain gun, a wooden block of mass M = 530.0 g is supported only by its edges, and a bullet of mass m = 7.25 g is fired vertically upward into the block from close range below. After the bullet embeds itself in the block, the block and the bullet are measured to rise to a maximum height of 30.0 cm above the block's original position. What is the speed of the bullet just before impact? m/s

Velocity of bullet = 179.33 m/s

Explanation:

Given:

Mass of block(M) = 530g

Mass of bullet(m) = 7.25g

Height (h) = 30 cm = 0.30 m

Find:

Speed of bullet before impact.

Computation:

After impact velocity (v) =                [∵ g = 9.8]

After impact velocity (v) = 2.42 m/s

Law of conservation .

(M+m)v = M(velocity of block) + m(Velocity of bullet)

(530+7.25)(2.42) = 530(0) + 7.25(Velocity of bullet)

Velocity of bullet = 179.33 m/s

it should be -8.6 cm hope this out

1 a

2 b

3 b

4 d

5 d

6 d

explanation: