CAN YOU HELP ME PL +40P A container with a volume of 3 liters contains a gas at 27°C and 2 atmospheric pressure. Find the work this gas does during the following operations. a) Its temperature is increased 5 times in constant volume b) Its volume is increased 4 times in constant pressure from the beginning. c) Its volume is doubled from the beginning.

Explanation:

main equation we need is

for Work done the equation is

W = P . ∆V (for isobar or constant pressure and isovolume or constant volume)

W = nRT ln V2/V1 (for isothermal or constant temperature)

p = pressure

v = volume

t = temperature (in Kelvin)

w = work

t = 27° C = 300 K

a. constant volume means ∆V (change on volume) is 0. So the work done in this process is 0

b. constant pressure (using SI unit)

W = P . ∆V = 2 . 1.01 . 10⁵ Pa . (12 - 3) . 10-³ m³ = 1 818 Joule

c. it's not clear in what operation in this process. but we can assume the process same with b (because if we will use constant temperature, there isn't any number for mol n) so

W = P . ∆V = 2 . 1.01 . 10⁵ Pa . (6 - 3) . 10-³ m³ = 606 Joule

hope this can help you

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.