Please help, will mark brainliest (a) A freezer maintains an interior temperature inside of −12.0°C and has a coefficient of performance of 3.00. The freezer sits in a room with a temperature of 19.0°C. The freezer is able to completely convert 26.0 g of liquid water at 19.0°C to ice at −12.0°C in one minute. What input power (in watts) does the freezer require? (The specific heat of liquid water is 4.186 J/(g · °C), the specific heat of ice is 2.090 J/(g · °C), and the latent heat of fusion of water is 334 J/g.)

(b) What If? In reality, only part of the power consumption of a freezer is used to make ice. The remainder is used to maintain the temperature of the rest of the freezer. Suppose, however, that 100% of a freezer's typical power consumption of 160 W is available to make ice. The freezer has the same coefficient of performance as given above. How many grams per minute of water at 19.0°C could this freezer convert to ice at −12.0°C? g/min

Freezer requires 55,49 W of input of energy and the 25 g/ min of water at 19.0°C, this freezer convert to ice at −12.0°C.

(A)

Since, mass is constant.

Thus,

...........1

But on conversion from water to ice at 0°c

Q  = m x Lf...........2

From equation 1 and 2,

26 ×4.186 ×(0-19) -26 ×334 + 26 × 2.090× (-12-0)

=2067.884 + 8684 + 652.08 = 9988.16 J

From performance formula;

Where,

Pi - power input

Po - Power output

CoP - Coefficient of power

(B)

Since, the negative sign indicate the lost of heat from the system.

Calculate Energy per unit mass of the given process

9988.16J/26 =384.16 J/g

Power consumption =  160 W

Since, the whole process takes 60s.

160 ×60 J = 9600 J

But the output energy per unit mass is 384.16J/g.

Hence the required mass for 9600J,

9600/384.16= 24.99g = 25 g/min

Therefore, freezer requires 55,49 W of input of energy and the 25 g/ min of water at 19.0°C, this freezer convert to ice at −12.0°C.

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A.55.49W, B. 25g

Explanation:

The heat required to free the water at 17°c is that required to reduce it to water at 0°c plus that to convert it to ice at 0°c plus that required to get it to ice at -12°c.

Note that in the conversion process mass is constant.

Hence the heat extracted is defined as mass ×specific heat capacity × temperature change.

But on conversion from water to ice at 0°c the heat extracted is mass × latent heat of fusion.

Putting all together we have :

26 ×4.186 ×(0-19) -26 ×334 + 26 × 2.090× (-12-0)

=2067.884+8684+652.08=9988.16J

This is the output power

From performance formula;

Coefficient of performance=output power /input power

Input power = output power / coefficient of performance

Input power=9988.16J/3 =3329.39j

In watt we divide by 60

3329.39/60= 55.49W

Note the negative sign is just an indication that heat is been lost from the system.

B. Let's calculate Energy per unit mass of the process

9988.16J/26 =384.16J/g

Power consumption is 160w

This is the input power of the system

160 W is available to make ice.

This means 160 ×60 J is the energy available to make ice since the whole process takes 60s.

That energy =9600J

But the output energy per unit mass is 384.16J/g.

Hence the required mass for 9600J is

9600/384.16= 24.99g

Approximately 25g

the total distance traveled by the car is

30km + 49km = 79 km .

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles