An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field in the wire changes with time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is measured in seconds.

Complete Question

An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field in the wire changes with time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is measured in seconds.

I = 1.2 A at time 5 secs.

Find the charge Q passing through a cross-section of the conductor between time 0 seconds and time 5 seconds.

The charge is  

Explanation:

From the question we are told that

    The diameter of the wire is  

     The radius of  the wire is  

     The resistivity of aluminum is

       The electric field change is mathematically defied as

Generally the charge is  mathematically represented as

Where A is the area which is mathematically represented as

 So

Therefore

substituting values

From the question we are told that t =  5 sec

compass can be used day and night, cloudy or sunny

conservation of mass

mass before something happens = mass afterwards