Physics, 10.06.2020 07:57 meowmeowcow

Please Help! T = 2π√*(l/g) T = period, l = length and g = acceleration due to gravity

g = 9.80 m/s2 on Earth, gJupiter = 24.6 m/s2 on Jupiter

Using the formula above, algebraically solve for 1.

Step 1: Divide both sides by 2π T/2π = √l/g

Step 2: Square both sides T2/4π2 = l/g

Step 3: Multiply both sides g gT2/4π2 = l

How long does the string need to be if I want to make a period of one oscillation per second? What about on Jupiter?

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Please Help! T = 2π√*(l/g) T = period, l = length and g = acceleration due to gravity

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