Coulomb's law: A point charge Q is located a short distance from a point charge 3 Q, and no other charges are present. If the electrical force on Q is F, what is the electrical force on 3 Q

The electrical force on 2nd charge (3 Q) will also be equal to F.

Explanation:

The electrical force between two electrically charged particles is given by the Coulomb's Law. The mathematical formula of Coulomb's Law is as follows:

F = kQ₁Q₂/r²

where,

F = Electrical Force exerted by both particles on each other

k = Coulomb's Constant

Q₁ = Magnitude of 1st Charge = Q

Q₂ = Magnitude of 2nd Charge = 3 Q

r = Distance between the charges

Therefore,

F = k(Q)(3 Q)/r²

F = 3 kQ²/r²

Since, it is clear from the formula that the magnitude of force applied by the first charge on 2nd charge is equal to the force applied by 2nd charge on 1st charge.

Therefore, the electrical force on 2nd charge (3 Q) will also be equal to F.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

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