A spherical conductor with a 0.103 m radius is initially uncharged. How many electrons should be removed from the sphere in order for it to have an electrical potential of 4.50 kV at the surface

Explanation:

capacitance of the capacitor C = 4πε₀R

= 1 x .103 / (9 x 10⁹ )  [ 1/ 4πε₀  = 9 x 10⁹ . ]

= .0114 x 10⁻⁹ F

potential  V = 4.5 x 10³ v

charge Q = CV

.0114 x 10⁻⁹  x 4.5 x 10³

= .0515 x 10⁻⁶ C

charge on one electron = 1.6 x 10⁻¹⁹

no of electrons to be removed

= .0515 x 10⁻⁶ / 1.6 x 10⁻¹⁹

= .032 x 10¹³

3.2 x 10¹¹ electrons.

measure their densities same density, same sub