Arectangular plate has a length of (22.4 ± 0.2) cm and a width of (8.4 ± 0.1) cm. calculate the area of the plate, including its uncertainty.

To answer this problem, we can use the lower and upper limits altogether of the dimensions given. In this case, the minimum area is the product of 22.2 cm and 8.3 cm that is equal to 184.26 cm2 while the maximum area is equal to 22.6 cm times 8.5 cm equal to 192. 1 cm2. Plainly, 22.4 cm times 8.4 cm is equal to 188.16 cm2. The area is equal then to 188.16 +- 3.9 cm2

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