A 75kg student is climbing a rock face with a constant speed. Neglect any friction and drag impeding her motion. How much force is the student generating up the hill?

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The answer is 4f======since electrostatic force is given by    we let f be the electrostatic force when  r = 1 m    if we let  denote the electrostatic force when the distance is decreased so that r = 0.5m, then    we established earlier that f = kq₁q₂. therefore    the force will now be 4f.

Simple, don't do it. just don't go to that dock

Gotta have a picture ^^