for a fluid flowing at a velocity v in a tube of cross-sectional area A, VA=constant. state two assumptions made in deriving this equation

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered

higher potential

explanation:

because it is in a high speed so it must move into a of high potential

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j