HELP ASAP!! A 41kg girl sits on the edge of a merry-go-round. If she travels
at 0.02ms and the radius of her motion is 2.1m, what is the centripetal force acting upon her?

Centripetal force F = 0.0078 N

Explanation: Given that the

Mass M = 41 kg

Velocity V = 0.02 m/s

Radius r = 2.1 m

Centripetal force F = MV^2/r

Substitutes all the parameters into the formula

F = (41 × 0.02^2)/2.1

F = ( 41 × 0.0004 )/2.1

F = 0.0164/2.1

F = 0.0078 N

The centripetal force acting upon her is 0.0078 Newton

t.                 w               e                 n                   t                 y                 c             h               a           r           a               c                 t             e             r             s        

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)