It takes 56.6 joules of energy to raise the temperature of 150 milliliters of water from 5 degrees celsius to 95 degree celsius if you use an electric water heater that is 60% efficient how many kilojoules of energy will the heater actually use by the time the water reaches it's final temperature

If 56.6J = 60%,

then 56.6/0.6 =  94.3333 J = 0.0943... kJ

The rest of the information (mL and temperature change) isn't needed for the answer...

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