Physics questions regarding circuits and electricity.

A. 1.5A.

B. 3V

C. 4.5V

D. 1.5V

E. 9V

Explanation:

A. Determination of the current in the circuit.

We'll begin by calculating the total resistance. This is illustrated below:

R1 = 2Ω

R2 = 3Ω

R3 = 1Ω

Total resistance (RT) =..?

RT = R1 + R2 + R3

RT = 2 + 3 + 1

RT = 6Ω

Therefore, the total resistance is 6Ω.

Now, we can obtain the current in the circuit as follow:

Voltage(V) = 9V

Total Resistance (R) = 6Ω

Current (I) =..?

V = IR

I = V /R

I = 9/6

I = 1.5A

Therefore, the current in the circuit is

B. Determination of the voltage across 2Ω resistor.

Resistor (R) = 2Ω

Current (I) = 1.5A

Voltage (V) =..?

V = IR

V = 1.5 x 2

V = 3V.

Therefore, the voltage across 2Ω resistor is 3V.

C. Determination of the voltage across 3Ω resistor.

Resistor (R) = 3Ω

Current (I) = 1.5A

Voltage (V) =..?

V = IR

V = 1.5 x 3

V = 4.5V.

Therefore, the voltage across 3Ω resistor is 4.5V.

D. Determination of the voltage across 1Ω resistor.

Resistor (R) = 1Ω

Current (I) = 1.5A

Voltage (V) =..?

V = IR

V = 1.5 x 1

V = 1.5V.

Therefore, the voltage across Ω resistor is 1.5V.

E. Determination of the sum of the voltage across all three resistor.

Voltage across 2Ω (V1) = 3V

Voltage across 3Ω (V2) = 4.5V

Voltage across 1 (V3) = 1.5V

Total voltage (VT) =..?

VT = V1 + V2 + V3

VT = 3 + 4.5 + 1.5

VT = 9V

Therefore, the sum of the voltage across all three resistor is 9V.

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.