Physics questions regarding circuits and electricity.

A. 3Ω.

B. 2A.

C. 2V.

D. 4V.

Explanation:

A. Determination of the total resistance.

Resistance 1 (R1) = 1Ω

Resistance 2 (R2) = 2Ω

Total resistance (RT) =..?

Since the resistance are in series connection, the total resistance can be obtained by adding both resistance as shown below:

RT = R1 + R2

RT = 1 + 2

RT = 3Ω

Therefore, the total resistance is 3Ω

B. Determination of the current in the circuit.

Voltage (V) = 6V

Total resistance (R) = 3Ω

Current (I) =..?

V = IR

I = V /R

I = 6/3

I = 2A.

Therefore, the current flowing in the circuit is 2A.

C. Determination of the voltage across 1Ω resistance.

Resistance (R) = 1Ω

Current (I) = 2A

Voltage (V) =..?

V = IR

V = 2 x 1

V = 2V.

Therefore, the voltage across 1Ω resistance is 2V.

D. Determination of the voltage across 2Ω resistance.

Resistance (R) = 2Ω

Current (I) = 2A

Voltage (V) =..?

V = IR

V = 2 x 2

V = 4V.

Therefore, the voltage across 2Ω resistance is 4V.

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